Fourier Reciprocity & Parseval's Identity
Energy Conservation and Convergence on the Circle
We begin by considering the Fourier Reciprocity Formula and how it naturally extends to Parseval's Identity. Consider a function represented by its complex Fourier series:
Convergence and the Weierstrass M-Test
To ensure our function is continuous and bounded, we assume the coefficients are absolutely summable: \(\sum |C_n| < \infty\). By the Weierstrass M-Test, this guarantees uniform and absolute convergence.
The M-Test: If \(|f_n(x)| \leq M_n\) and \(\sum M_n\) converges, then \(\sum f_n(x)\) converges uniformly.
In our case: \(|C_n e^{in\theta}| = |C_n|\). Since \(\sum |C_n|\) converges, our function \(f(\theta)\) is continuous and finite on the circle \(\mathbb{T} = (-\pi, \pi]\).
The Orthogonality Principle
The backbone of this proof is the orthogonality of the complex exponentials:
Deriving the Reciprocity Formula
Let \(g \in L^1(\mathbb{T})\) with Fourier coefficients \(D_n\). We look at the integral of the product of two functions:
Note that \(\int g(\theta)e^{in\theta}d\theta\) is almost the definition of \(D_{-n}\). This gives us:
Fourier Reciprocity Formula
Parseval's Identity
By letting \(g = \bar{f}\) (the complex conjugate), we transform the left side into the energy of the signal. Since \(f\bar{f} = |f|^2\), we ensure the result is real-valued.
Parseval's Identity on the Circle
This identity is profound: it states that the total "energy" of a signal (left) is equal to the sum of the energies of its individual frequency components (right).